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How Can a Formula 1 Car Drive Upside Down and Defy Gravity?

Can an F1 car really do that?

By Lucian Dorneanu, Science Editor

17th of May 2007, 21:06 GMT

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The F1 car driven by Juan Pablo Montoya in 2005
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Many car enthusiasts or Formula One fans around the world have heard the statement: 'A Formula 1 car can drive upside down without falling.'

Is it true? And if yes, how do they do it?

If you thought abound the car's aerodynamics, you were right, but let's see exactly what are the equipments and the conditions to make this happen.

First, let's take a look at a plane. The wing of an airplane produces lifting force. Lifting is a mechanical force generated by a solid object moving through a fluid. The shape of the wing directs the airflow so that the air moving over the top of the wing is moving faster, thus creating an area of lower pressure than the one beneath.

The pressure difference lifts the airplane off the ground when a certain speed is reached, and that depends on the propulsion system and wing
finetuning.

F1 cars have two aerodynamic wings, one in the front and one in the back. The only difference is that they look exactly like an upside down airplane wing. So, instead of generating lift, they generate downforce, that sticks the car to the ground.

Many minimum speeds are reported throughout the Internet, some saying that the car must reach 200 km/h to be able to stick a ceiling, when in fact an F1 car achieves the necessary downforce at 125 km/h to 130 km/h. At 190 km/h the downforce to weight ratio is roughly 2:1.

What most people don't know is that F1 regulations prohibit the use of ground effect elements that act to increase the downforce, so the underside of the vehicle, the undertray, must be flat between the axles. Thus, the car relies only on its two deflector wings and small winglets on the sides to achieve this effect.

Unfortunately, so far no real test has been performed to prove the efficacy of this effect, or at least none has been published.

Computer simulation of the airflow around an F1 car in the windtunnel
Enlarge picture
The ideal environment to do that would be in a perfectly cylindrical tunnel, where the car would start on the ground and very quickly climb the lateral "walls" to get to the "roof." However, in the time it takes the car to get from bottom to top, there would be no downforce to keep it from falling.

So, when the car will be on the "walls", it will surely fall, and this is probably since no one has attempted this so far.

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car | engine | vehicle | force | speed
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User opinions:


Comment #1 by: zonervan on 01 Apr 2008, 20:16 GMT reply to this comment

They trick to test this theory is not to drive the car up a wall, but rather to build a track that spins in a screw like a roller coaster. This would insure that the car makes no change to its forward speed or changes the direction of the air over the wings.


Comment #2 by: Conor Anderson on 22 Apr 2008, 16:46 GMT reply to this comment

This is very helpful as I am doing a science project- thank you!!


Comment #3 by: Tony Rule on 16 Sep 2008, 22:32 GMT reply to this comment

The principle that allows the force to be generated by the wings is the same as that on the wings of a plane, only upside down. The force acts perpendicular to the wing, not the ground so the car will not fall off the side during the ascent - it will still be pinned there at whatever angle to the ground provided there is sufficient speed. to generate the force. When the wing is not parallel to the ground (in the ascent) there will be gravity to contend with on a vector basis but that's not particularly significant or substantial.


Comment #4 by: Carlo Raponi on 19 Sep 2008, 01:18 GMT reply to this comment

I don't think it's possible. Google it.


Comment #5 by: Max on 05 Jan 2009, 18:19 GMT reply to this comment

I think this is absolutely doable. Given there is a perfect tunnel that will permit the closure to traffic to do this. The driver can slalom through all the hanging signs, given there is enough distance between the signs. This can be fun:)


Comment #6 by: Bryan on 11 Feb 2009, 04:36 GMT reply to this comment

This is totally possible if the tunnels in the car are producing it to go down then in the tunnel no matter how high up or even upside down it is. As long as the force of the wind, supporting the fact the speed remains abouve 190, would force against the gravitational pull of the earth.


Comment #7 by: Chris on 23 Mar 2009, 13:24 GMT reply to this comment

The article is WRONG. The last 2 paragraphs imply the car will fall off the "wall" on the way to the ceiling. The car will be forced into the ground, walls, ceiling, whatever. As long as speed is maintained, the air moving over the wings and body will force the car "down" with respect to the car's orientation. So no, the car will not fall off the "wall" on the way to the ceiling.
It's physics, not opinion.

Comment #7.1 by: Mitch on 04 May 2009, 14:04 GMT

Yes it's physics not opinion, unfortunately your physics is wrong. Perpendicular vectors are independent of each other, so even though the downforce would be opposing the horizontal force of the wall, only friction would be opposing the force of gravity. This differs totally to when the car is on the ceiling as the downforce would directly oppose to force of gravity.

Comment #7.2 by: Dino on 24 May 2009, 20:01 GMT

Thanks for the full explanation, Mitch. I was wondering the same thing when I read that part.


Comment #8 by: Bubba on 15 Jun 2009, 15:37 GMT reply to this comment

Chris is right, Mitch is wrong. The position of the surface relative to gravity is irrelevant. That's the whole point. If anything, the slight frictional advantage of being on the wall as opposed to on the ceiling would HELP the car stay glued to the surface, not cause it to fall. If the downforce is adequate, the car is not dependent on being at any particular portion of the tubular raceway. It should stick no matter WHERE it is driving. The ONLY consideration is how quickly the car steers toward the roof. Too quick a motion will affect the way the inverted wing performs, thus reducing it's downforce....how much is up for debate.

Mitch hasn't thought this through.


Comment #9 by: JSF on 29 Jul 2009, 05:52 GMT reply to this comment

How about they get on this and test it, and stop wondering?

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